Optimal. Leaf size=161 \[ a^2 \sin (c) \text{CosIntegral}(d x)+a^2 \cos (c) \text{Si}(d x)+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 a b \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}-\frac{60 b^2 x^2 \sin (c+d x)}{d^4}+\frac{20 b^2 x^3 \cos (c+d x)}{d^3}+\frac{120 b^2 \sin (c+d x)}{d^6}-\frac{120 b^2 x \cos (c+d x)}{d^5}-\frac{b^2 x^5 \cos (c+d x)}{d} \]
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Rubi [A] time = 0.256466, antiderivative size = 161, normalized size of antiderivative = 1., number of steps used = 14, number of rules used = 7, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.368, Rules used = {3339, 3303, 3299, 3302, 3296, 2638, 2637} \[ a^2 \sin (c) \text{CosIntegral}(d x)+a^2 \cos (c) \text{Si}(d x)+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{4 a b \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}-\frac{60 b^2 x^2 \sin (c+d x)}{d^4}+\frac{20 b^2 x^3 \cos (c+d x)}{d^3}+\frac{120 b^2 \sin (c+d x)}{d^6}-\frac{120 b^2 x \cos (c+d x)}{d^5}-\frac{b^2 x^5 \cos (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 3339
Rule 3303
Rule 3299
Rule 3302
Rule 3296
Rule 2638
Rule 2637
Rubi steps
\begin{align*} \int \frac{\left (a+b x^3\right )^2 \sin (c+d x)}{x} \, dx &=\int \left (\frac{a^2 \sin (c+d x)}{x}+2 a b x^2 \sin (c+d x)+b^2 x^5 \sin (c+d x)\right ) \, dx\\ &=a^2 \int \frac{\sin (c+d x)}{x} \, dx+(2 a b) \int x^2 \sin (c+d x) \, dx+b^2 \int x^5 \sin (c+d x) \, dx\\ &=-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^5 \cos (c+d x)}{d}+\frac{(4 a b) \int x \cos (c+d x) \, dx}{d}+\frac{\left (5 b^2\right ) \int x^4 \cos (c+d x) \, dx}{d}+\left (a^2 \cos (c)\right ) \int \frac{\sin (d x)}{x} \, dx+\left (a^2 \sin (c)\right ) \int \frac{\cos (d x)}{x} \, dx\\ &=-\frac{2 a b x^2 \cos (c+d x)}{d}-\frac{b^2 x^5 \cos (c+d x)}{d}+a^2 \text{Ci}(d x) \sin (c)+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}+a^2 \cos (c) \text{Si}(d x)-\frac{(4 a b) \int \sin (c+d x) \, dx}{d^2}-\frac{\left (20 b^2\right ) \int x^3 \sin (c+d x) \, dx}{d^2}\\ &=\frac{4 a b \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{20 b^2 x^3 \cos (c+d x)}{d^3}-\frac{b^2 x^5 \cos (c+d x)}{d}+a^2 \text{Ci}(d x) \sin (c)+\frac{4 a b x \sin (c+d x)}{d^2}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}+a^2 \cos (c) \text{Si}(d x)-\frac{\left (60 b^2\right ) \int x^2 \cos (c+d x) \, dx}{d^3}\\ &=\frac{4 a b \cos (c+d x)}{d^3}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{20 b^2 x^3 \cos (c+d x)}{d^3}-\frac{b^2 x^5 \cos (c+d x)}{d}+a^2 \text{Ci}(d x) \sin (c)+\frac{4 a b x \sin (c+d x)}{d^2}-\frac{60 b^2 x^2 \sin (c+d x)}{d^4}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}+a^2 \cos (c) \text{Si}(d x)+\frac{\left (120 b^2\right ) \int x \sin (c+d x) \, dx}{d^4}\\ &=\frac{4 a b \cos (c+d x)}{d^3}-\frac{120 b^2 x \cos (c+d x)}{d^5}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{20 b^2 x^3 \cos (c+d x)}{d^3}-\frac{b^2 x^5 \cos (c+d x)}{d}+a^2 \text{Ci}(d x) \sin (c)+\frac{4 a b x \sin (c+d x)}{d^2}-\frac{60 b^2 x^2 \sin (c+d x)}{d^4}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}+a^2 \cos (c) \text{Si}(d x)+\frac{\left (120 b^2\right ) \int \cos (c+d x) \, dx}{d^5}\\ &=\frac{4 a b \cos (c+d x)}{d^3}-\frac{120 b^2 x \cos (c+d x)}{d^5}-\frac{2 a b x^2 \cos (c+d x)}{d}+\frac{20 b^2 x^3 \cos (c+d x)}{d^3}-\frac{b^2 x^5 \cos (c+d x)}{d}+a^2 \text{Ci}(d x) \sin (c)+\frac{120 b^2 \sin (c+d x)}{d^6}+\frac{4 a b x \sin (c+d x)}{d^2}-\frac{60 b^2 x^2 \sin (c+d x)}{d^4}+\frac{5 b^2 x^4 \sin (c+d x)}{d^2}+a^2 \cos (c) \text{Si}(d x)\\ \end{align*}
Mathematica [A] time = 0.511934, size = 108, normalized size = 0.67 \[ a^2 \sin (c) \text{CosIntegral}(d x)+a^2 \cos (c) \text{Si}(d x)+\frac{b \left (4 a d^4 x+5 b \left (d^4 x^4-12 d^2 x^2+24\right )\right ) \sin (c+d x)}{d^6}-\frac{b \left (2 a d^2 \left (d^2 x^2-2\right )+b x \left (d^4 x^4-20 d^2 x^2+120\right )\right ) \cos (c+d x)}{d^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.017, size = 487, normalized size = 3. \begin{align*}{\frac{ \left ({c}^{5}+{c}^{4}+{c}^{3}+{c}^{2}+c+1 \right ){b}^{2} \left ( - \left ( dx+c \right ) ^{5}\cos \left ( dx+c \right ) +5\, \left ( dx+c \right ) ^{4}\sin \left ( dx+c \right ) +20\, \left ( dx+c \right ) ^{3}\cos \left ( dx+c \right ) -60\, \left ( dx+c \right ) ^{2}\sin \left ( dx+c \right ) +120\,\sin \left ( dx+c \right ) -120\, \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{6}}}-6\,{\frac{c{b}^{2} \left ({c}^{4}+{c}^{3}+{c}^{2}+c+1 \right ) \left ( - \left ( dx+c \right ) ^{4}\cos \left ( dx+c \right ) +4\, \left ( dx+c \right ) ^{3}\sin \left ( dx+c \right ) +12\, \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) -24\,\cos \left ( dx+c \right ) -24\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{6}}}+15\,{\frac{ \left ({c}^{3}+{c}^{2}+c+1 \right ){c}^{2}{b}^{2} \left ( - \left ( dx+c \right ) ^{3}\cos \left ( dx+c \right ) +3\, \left ( dx+c \right ) ^{2}\sin \left ( dx+c \right ) -6\,\sin \left ( dx+c \right ) +6\, \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{6}}}+2\,{\frac{ \left ({c}^{2}+c+1 \right ) ab \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{3}}}-20\,{\frac{{b}^{2}{c}^{3} \left ({c}^{2}+c+1 \right ) \left ( - \left ( dx+c \right ) ^{2}\cos \left ( dx+c \right ) +2\,\cos \left ( dx+c \right ) +2\, \left ( dx+c \right ) \sin \left ( dx+c \right ) \right ) }{{d}^{6}}}-6\,{\frac{cab \left ( 1+c \right ) \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{3}}}+15\,{\frac{ \left ( 1+c \right ){b}^{2}{c}^{4} \left ( \sin \left ( dx+c \right ) - \left ( dx+c \right ) \cos \left ( dx+c \right ) \right ) }{{d}^{6}}}-6\,{\frac{{c}^{2}ab\cos \left ( dx+c \right ) }{{d}^{3}}}+6\,{\frac{{b}^{2}{c}^{5}\cos \left ( dx+c \right ) }{{d}^{6}}}+{a}^{2} \left ({\it Si} \left ( dx \right ) \cos \left ( c \right ) +{\it Ci} \left ( dx \right ) \sin \left ( c \right ) \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [C] time = 35.6874, size = 198, normalized size = 1.23 \begin{align*} \frac{{\left (a^{2}{\left (-i \,{\rm Ei}\left (i \, d x\right ) + i \,{\rm Ei}\left (-i \, d x\right )\right )} \cos \left (c\right ) + a^{2}{\left ({\rm Ei}\left (i \, d x\right ) +{\rm Ei}\left (-i \, d x\right )\right )} \sin \left (c\right )\right )} d^{6} - 2 \,{\left (b^{2} d^{5} x^{5} + 2 \, a b d^{5} x^{2} - 20 \, b^{2} d^{3} x^{3} - 4 \, a b d^{3} + 120 \, b^{2} d x\right )} \cos \left (d x + c\right ) + 2 \,{\left (5 \, b^{2} d^{4} x^{4} + 4 \, a b d^{4} x - 60 \, b^{2} d^{2} x^{2} + 120 \, b^{2}\right )} \sin \left (d x + c\right )}{2 \, d^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.74802, size = 373, normalized size = 2.32 \begin{align*} \frac{2 \, a^{2} d^{6} \cos \left (c\right ) \operatorname{Si}\left (d x\right ) - 2 \,{\left (b^{2} d^{5} x^{5} + 2 \, a b d^{5} x^{2} - 20 \, b^{2} d^{3} x^{3} - 4 \, a b d^{3} + 120 \, b^{2} d x\right )} \cos \left (d x + c\right ) + 2 \,{\left (5 \, b^{2} d^{4} x^{4} + 4 \, a b d^{4} x - 60 \, b^{2} d^{2} x^{2} + 120 \, b^{2}\right )} \sin \left (d x + c\right ) +{\left (a^{2} d^{6} \operatorname{Ci}\left (d x\right ) + a^{2} d^{6} \operatorname{Ci}\left (-d x\right )\right )} \sin \left (c\right )}{2 \, d^{6}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 9.35425, size = 211, normalized size = 1.31 \begin{align*} a^{2} \sin{\left (c \right )} \operatorname{Ci}{\left (d x \right )} + a^{2} \cos{\left (c \right )} \operatorname{Si}{\left (d x \right )} + 2 a b x^{2} \left (\begin{cases} - \cos{\left (c \right )} & \text{for}\: d = 0 \\- \frac{\cos{\left (c + d x \right )}}{d} & \text{otherwise} \end{cases}\right ) - 4 a b \left (\begin{cases} - \frac{x^{2} \cos{\left (c \right )}}{2} & \text{for}\: d = 0 \\- \frac{\begin{cases} \frac{x \sin{\left (c + d x \right )}}{d} + \frac{\cos{\left (c + d x \right )}}{d^{2}} & \text{for}\: d \neq 0 \\\frac{x^{2} \cos{\left (c \right )}}{2} & \text{otherwise} \end{cases}}{d} & \text{otherwise} \end{cases}\right ) + b^{2} x^{5} \left (\begin{cases} - \cos{\left (c \right )} & \text{for}\: d = 0 \\- \frac{\cos{\left (c + d x \right )}}{d} & \text{otherwise} \end{cases}\right ) - 5 b^{2} \left (\begin{cases} - \frac{x^{5} \cos{\left (c \right )}}{5} & \text{for}\: d = 0 \\- \frac{\begin{cases} \frac{x^{4} \sin{\left (c + d x \right )}}{d} + \frac{4 x^{3} \cos{\left (c + d x \right )}}{d^{2}} - \frac{12 x^{2} \sin{\left (c + d x \right )}}{d^{3}} - \frac{24 x \cos{\left (c + d x \right )}}{d^{4}} + \frac{24 \sin{\left (c + d x \right )}}{d^{5}} & \text{for}\: d \neq 0 \\\frac{x^{5} \cos{\left (c \right )}}{5} & \text{otherwise} \end{cases}}{d} & \text{otherwise} \end{cases}\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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